Question

multiply the polynomial below:

Answer 1

\[\frac{ x^2-2x-8 }{ 6x^2-24x } \times \frac{ 2x^2-3x-2}{ x^2-4 }\]

Answer 2

i imagine your job is to factor as much as you can and then cancel

Answer 3

ok hold on let me try

Answer 4

for example \(x^2-2x-8=(x-4)(x+2)\) and you will also get a factor of \((x+2)\) in the denominator because \(x^2-4=(x+2)(x-2)\)

Answer 5

\[\frac{ 2x^2-7x-4 }{ x^2-4}\]

Answer 6

i think you can do more

Answer 7

-7x?

Answer 8

-7x-1?

Answer 9

ok lets go ahead and factor

Answer 10

wait 2-7x +1
3-7x

Answer 11

\[\frac{ x^2-2x-8 }{ 6x^2-24x } \times \frac{ 2x^2-3x-2}{ x^2-4 }\]
\[\frac{(x-4)(x+2)(x-2)(2x+1)}{6x(x-4)(x+2)(x-2)}\]

Answer 12

cancel away and you are not left with much
just
\[\frac{2x+1}{6x}\]

Answer 13

thank you

Answer 14

yw