Question

∫e^(2t)sin(3t)dx, integral, can someone help me and explain with details!

Answer 1

lol...is it dx or dt?

Answer 2

sorry dt

Answer 3

USe Integration by parts...

Answer 4

could you explain more cuz it confused me

Answer 5

Integration by parts...

let

u = sin3t dv = e^(2t) dt

du = 3cos3t dt v = e^(2t)/2

Answer 6

you should use intagration by parts:
u=e^2t
dv=sin3t dt
&
du=2e^2t dt
v=-1/3cos(3t)
-> uv-int(vdu)
(e^2t)(-1/3cos(3t))+int((2/3)cos(3t)(e^2t))dt
againu should use integration y parts
u=e^2t
dv=cos3t)
&du=2e^2t
v=1/3sin(3t)
(e^2t)(1/3sin(3t))-int((1/3sin3t)(2e^2t))dt
and we must name the phrase:((sin3t)(e^2t)) for example I and the equation solved