Question

Find the product of (4x − 3y)^2.

16x^2 + 24xy + 9y^2

16x^2 − 9y^2

16x^2 − 24xy + 9y^2

16x^2 + 9y^2

Answer 1

(4x − 3y) (4x − 3y)
16x^2 9y^2 how did i get 24xy

Answer 2

*do

Answer 3

you get -24xy by combining -12xy-12xy when you foil

Answer 4

(4x-3y)(4x-3y)=16x^2+9y^2-12xy-12yx=16x^2+9y^2-24yx

Answer 5

oh so 16^2+9y^2-24yx

Answer 6

16x^2+9y^2-24yx

Answer 7

yes that's right

Answer 8

or you could write it like this 16x^2-24xy+9y^2 which is the way I get it when I foil but its the same thing

Answer 9

So, to explain it, I'll make a little proof.
Say:
\[(a+b)^{2}\]
By definition we know that:
\[(a+b)^{2} = (a+b)(a+b)\]
There exists a property that is called "distributive, let's apply it:
\[a^{2}+ab+ba+b ^{2}\]
by conmutative, we know that "ab" and "ba" are equal:
So we get:
\[a ^{2}+2ab+b ^{2}\]

Good, but... Why did I do it?
looking at the problem:
\[(4x-3y)^{2}\]
Hey! it has the form of what I've just proven, so we can say that a=(4x) and b=(-3y)
we would end with this:
\[(4x)^{2}+2(4x)(-3y)+(-3y)^{2}\]
Operating it we get:
\[16x ^{2}-24xy+9y ^{2}\]
And you're ready to go :)

Answer 10

his answer is wrong dont believe it