"There should be one region that satisfies all of the inequalities in this problem. Identify this region by drawing the inequality lines and shading the region that satisfies all of the inequalities.
x>_0
x<_12
y<1/2x+6
x+3y>_12
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OpenStudy (anonymous):
the first one means you are to the right of the y axis
OpenStudy (anonymous):
the second one means you are to the left of \(x=12\)
OpenStudy (anonymous):
|dw:1379300137995:dw|
so you are between these two goal posts
OpenStudy (anonymous):
you already graphed \(y<\frac{1}{2}x+6\)
OpenStudy (anonymous):
|dw:1379300223856:dw|
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OpenStudy (anonymous):
one more to go
OpenStudy (anonymous):
what are the points for the last one?
OpenStudy (anonymous):
guess i made another mistake
OpenStudy (anonymous):
i just dont know which points to graph for x+3y>=12
OpenStudy (anonymous):
|dw:1379300550640:dw|
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OpenStudy (anonymous):
so i shade which part now?
OpenStudy (anonymous):
\(x+3y=12\) as \(y\) intercept \((0,4)\) as in the previous problem
also \(x\) intercept \((12,0)\)
OpenStudy (anonymous):
the middle stuff
OpenStudy (anonymous):
oh thats right! :)
OpenStudy (anonymous):
|dw:1379300645081:dw|
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