Mathematics
10 Online
OpenStudy (anonymous):
Solve the equation: √x+4=7
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OpenStudy (yttrium):
hey @charlieberzak , since I taught you some tips. Can you show me some solutions, you've got from this? :D
OpenStudy (anonymous):
\[\sqrt{x+4}=7\]
OpenStudy (anonymous):
thats how is should look like lol
OpenStudy (anonymous):
soo i should bring something to the other side?
OpenStudy (anonymous):
thats what u said last time...
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OpenStudy (yttrium):
No because it is also a part of the exponent. You square first the whole equation before transposing. :)
OpenStudy (anonymous):
O_o
OpenStudy (anonymous):
just square both side and separate variable and numbers
OpenStudy (yttrium):
As what we've said, you need to cancel the sqrt sign right? Therefore, what should you do first?
OpenStudy (anonymous):
ummm find x? which i think would be 3?
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OpenStudy (yttrium):
No, square 7 first. Before subtracting 4. :)
OpenStudy (anonymous):
rootx = 7-4
x square = 3 square , x = 9
OpenStudy (anonymous):
what do you mean by square?
OpenStudy (yttrium):
multiply 7 by itself.
OpenStudy (anonymous):
\[x ^{2}\]
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OpenStudy (anonymous):
7*7 = 49, is that what you mean?
OpenStudy (anonymous):
\[\sqrt{x} = 7 - 4\]
OpenStudy (anonymous):
the answer is 45!
OpenStudy (anonymous):
\[\sqrt{x} = 3\]
OpenStudy (yttrium):
Yes.
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OpenStudy (anonymous):
O.O
OpenStudy (yttrium):
Yes. You're right @charlieberzak , @JOELMATHEWS1234 maybe you misinterpreted the question.
OpenStudy (anonymous):
\[x = 9\]
OpenStudy (anonymous):
give the full question
OpenStudy (yttrium):
it's written in one of the comments.
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OpenStudy (anonymous):
oh , okay
OpenStudy (anonymous):
\[\sqrt{x + 4} = 7\]
OpenStudy (anonymous):
\[x + 4 = 7^{2}\]
OpenStudy (anonymous):
\[x = 49 -4 =45\]