Question

The Polynomial 3X^2+bx-4 has x-a as a factor where a is not equal to zero. express b in terms of a. HELP

Answer 1

@nelskie16
Let's have
\[\Large f(\color{red}x) = 3\color{red}x^2 + b\color{red}x - 4\]

Answer 2

And \(\Large \color{red}x-a\) is a factor, right?

Answer 3

yes. and x=a ?

Answer 4

What does it mean, if x - a is a factor?
it means
\[\Large f(\color{red}a) = 0\]
^_^

Can you work from there?

Answer 5

okay wait XD

Answer 6

can't , how please!. i can't understand the factorial theorem

Answer 7

It's factor theorem... and between you and me.. (ehem) kung mas gusto mo mag-tagalog na lang, ok lang sakin (ehem)

\[\Large f(\color{red}x) = 3\color{red}x^2 + b\color{red}x - 4\]\[\Large f(\color{red}a) =0\]\[\Large f(\color{red}a) = 3\color{red}a^2 + b\color{red}a - 4\]

Answer 8

paano po yan kuya! I mean, how to express b in terms of a?

Answer 9

TJ's rule number 1... wag ako gagamitan ng 'po' :P

Masdan mo... :D
\[\Large f(\color{red}a) = 0\]\[\Large f(\color{red}a) = 3\color{red}a^2 + b\color{red}a - 4\]

Then... since pareho sila f(a)
\[\Large 3a^2 + ba - 4 = 0\]

Answer 10

so yan na ung final answer? nde na po masimplify.

Answer 11

or iquadratic ko pa?

Answer 12

Kailangan mapag-isa mo yung b.
Parang pag-solve lang ng linear equation.

Solve for b.
Dalhin mo lahat ng term na walang b sa kabila...
\[\Large ba = 4-3a^2\]

Answer 13

\[b =\frac{ 4-3a ^{2} }{ a }\]

Answer 14

Bingo ^_^

Answer 15

so yan na po iyon? XD

Answer 16

O di ba? nasolve mo na yung b in terms of a (ie, a lang yung variable)

Answer 17

Sabing wag ako gagamitan ng po eh... di talaga marunong magbasa/makinig -.-

Answer 18

sorry. kasi eh XD. So kuya yan na yung sagot? yang equation na yan/formula

Answer 19

Yup :)

Answer 20

Salamat kuya! XD

Answer 21

;)