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Show that x-m is a factor x^a-m^a for any positive integer a
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@terenzreignz
hmm.. Factor theorem...
yup. :3
Well then, let \[\Large f(x) = x^a - m^a\]
will i just substitute m to x? and i get 0 right? is that the final answeR?
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Yup :) You just substitute m for x. and obviously, you get 0, which, by the factor theorem, is enough to conclude that x-m is a factor of \(\large x^a - m^a\)
oh. okaaay thanks. :333
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