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Mathematics 12 Online
OpenStudy (anonymous):

What is the solution of the equation? Eliminate any extraneous solutions.

OpenStudy (anonymous):

\[\sqrt{3x+28}-8\]

OpenStudy (debbieg):

That's not an equation, that's an expression. An equation has an equals sign somewhere.....

OpenStudy (anonymous):

its all equal to x

OpenStudy (anonymous):

\[\sqrt{3+28}-8=x\]

OpenStudy (anonymous):

@DebbieG

OpenStudy (debbieg):

ok, that' important to know, you can't just leave that out. Now you changed the expression under the radical.... I think just a typo, so is it: \(\sqrt{3x+28}-8=x\) You need to add 8 to both sides, to "isolate" the square root expression on one side (so it's by itself). then square both sides, which will eliminate the square root. Then solve the equation you have (it will be a quadratic) like you would normally. One last step: CHECK your solutions in the ORIGINAL equation!!! Very likely to get extraneous solutions, when you start squaring sides of an equation! :)

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