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Please help, how do I find the integral of tan(x).
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You mean inverse?
hello, dog avatar
lol hey
\[tan (x) = \frac {sin}{cos}\]just let u = cos, du =.... there is an outlet there
Isn't it 1/opp ---- hyp
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ok thanks loser
lol
hey, dog avatar, it's integral, it 's not trig
I mean integral of a trig function \[\int tan x~ dx\]
oh, I'm in pre calc now so ya...
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