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What is the equation of the line that passes through (2, 1) and is perpendicular to the graph of y = –x + 2? y = x – 1 y = x + 1 y = –x + 3 y = –x + 2
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The slope of y = -x+2 is -1
so the slope of any perpendicular line is 1 (flip the fraction, flip the sign)
y = mx + b y = 1*x + b ... plug in the perpendicular slope 1 = 1*2 + b ... plug in the given point 1 = 2 + b 1 - 2 = b -1 = b b = -1 So the equation of the perpendicular line is y = x - 1
thank you!
np
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