Question

find a so that the point (-1, 2) is on the graph of f(x)=ax^2+4

Answer 1

I dont just want an answer, I need help actually doing the problem please

Answer 2

You have:
\[f(x)=ax^2+4\]
We know that there exists an \(a\) such that:
\[2=f(-1)=a(-1)^2+4\]

Answer 3

So we can set up the equation:
\[2=a(-1)^2+4\]
And solve for \(a\)

Answer 4

one moment

Answer 5

Okay!

Answer 6

-2=a ?

Answer 7

Yeah, that's what the book says, thanks ^_^

Answer 8

Anytime flevine :)

Answer 9

-2=a ?

Answer 10

Yep