Compare y=1/2 |x+6| -2 with the parent function y=|x|. Without graphing, what are the vertex, axis of symmetry and transformations of the parent function?
do you know what |x| looks like?
where is the axis of symmetry for y=|x|?
Hmm.... Wouldn't it just be in the center? I'm confused.
I know that |x| is pretty much just 1x.
the change on the inside will move it the opposite direction left and right. so since we have a +6 on the inside it will move it 6 to the left, so the vertex went from (0,0) to (-6,0), does this make sense?
Yes, that makes sense.
ok now the -2 on the outside will move us down 2 so now our vertex is (-6,-2)
the x value here is also the axis of symmetry x=-6
the 1/2 will simply flatten it.
think about 1/2 |x| you put in 2 you get out 1 where with |x| you put in 2 and get out 2
Ok, I got that part.
thats everything
Easier than I thought, thank you a bunch!
np
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