Assume that there are 11 board members: 6 females, and 5 males including Huck. There are 5 tasks to be assigned randomly, including that of reserving a room for meetings.
Find the probability huck is given a task(I got the right answer)=210/462
Find the probability that Huck is given the task of reserving a room for meetings. lost at this point

Question

Assume that there are 11 board members: 6 females, and 5 males including Huck. There are 5 tasks to be assigned randomly, including that of reserving a room for meetings.
Find the probability huck is given a task(I got the right answer)=210/462
 Find the probability that Huck is given the task of reserving a room for meetings. lost at this point

anonymous · Answer

This is what I see: You already have the prob that huck is given a task. Now, what is the prob that the one task given to huck is this specific one? I can be wrong but it seems unlikely.

anonymous · Answer

btw, how did you come up with that right answer?

anonymous · Answer

Yes I do, I used combinations to solve it.  I calculated the sample size c(11,5)=462 then did c(10,4)=210 because one member of the group was gone and he took one task.  I think I have tried every other combination possible to solve the second part with zero luck.

anonymous · Answer

Is there anything you can do to isolate that one specific task?

anonymous · Answer

The answer for part 2 must be less than the answer for part 1 because of the additional restriction right?

anonymous · Answer

Yes it should be, this answer is a subset of the first answer

anonymous · Answer

Could it be as simple as multiplying the first answer by 1/5? The prob of picking one specific task out of 5 is 1/5. Totally guessing here. I forgot everything about this class.

anonymous · Answer

you just divide by 5

anonymous · Answer

yes yes it was, thank you I hate finites simplicity