how is the diode connected in the feedback path?

Question

anonymous · Answer

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anonymous · Answer

@CarlosGP could u please explain this precision rectifier?

anonymous · Answer

im confused about the diode voltage drop...

anonymous · Answer

hmm..sorry a voltage supply is connected to the non inverting terminal

anonymous · Answer

this is an inverting voltage follower..so the cathode would be at negative potential...is it correct?

anonymous · Answer

http://en.wikipedia.org/wiki/File:Op-Amp_Precision_Rectifier.svg actually this is the circuit that i wanted to draw.

anonymous · Answer

yeah..

anonymous · Answer

by opamp output..you mean the terminal to which anode terminal of the diode is connected ..right?

anonymous · Answer

you mean the load voltage will be the negative of Vin

anonymous · Answer

but usually dont we write the output of the opamp at the feedback junction...i mean does it change?

anonymous · Answer

ok..im just so confused with this,...damn

anonymous · Answer

wow..thats a neat explanation..thanks...but i have one more small doubt...generally when we talk of opamps where is the output voltage( ie Vout=K(V+ -V-)) ...is it AT the feedback junction or BEFORE or AFTER it?