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PROVE\quad THAT\quad 2{ n }^{ 2 }\ge { (n+1) }^{ 2 }\quad for\quad n\ge 3\quad mathematical\quad analysis\quad problem.
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\[PROVE\quad THAT\quad 2{ n }^{ 2 }\ge { (n+1) }^{ 2 }\quad for\quad n\ge 3\quad mathematical\quad analysis\quad problem.\]
I'm tempted to say induction... are we allowed?
this is a mathematical analysis problem.
yes it is, induction is allowed.
Well, first, show that it holds for n = 3.
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yes i have done that i got 18>16.
Now, assume it holds for n = k, where k is some integer greater than or equal to 3. That is to say, this statement \[\Large 2k^2 \ge (k+1)^2 \qquad k\ge3\] is true.
ok.
now we have to show that it is true for (k+1) term right ?
that's right :) Try it ^_^
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we get 2|dw:1379425898720:dw|
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