For what values of a and b is the line 3 x + y = b tangent to the curve y = a x^{2} when x = 5?
@jolee 3x+y=b Can you find the slope of this line?
simple. 3.
3 is final srry
think about it
I tried 3=2ax is this wrong approach? (2ax by taking derivative of y=ax^2
\[3x+y=b\] taking derivative w.r.t x \[3+\frac{dy}{dx}=0\] \[\frac{dy}{dx}=-3\] which is the slope
but according to form mx+b, shouldn't slope be 3
3x+y=b y=-3x+b y=mx+b Comparing both m=-3, b=b
omg! what a stupid mistake of mine!! thank you
so a would equal -3/10
yes, right
We know that tangent is at point x=5, from this find y coordinate of the point and then use the line equation to find b
and do u know why we use radians in calc?
Suppose you have sin x, it's domain is real no.s x=1, 2, 3, these all are radians Using degrees in calculator, you have to convert them first
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