Indicate in standard form the equation of the line passing through the given point and having the given slope. A(5, 5), m = 3
i really need help
so u have x = 5 , y =5 and m is 3 , use the y = mx + c to find contant !!
that's the standard line formula
ok so how would it come out in the the formula like what would it look like
come on , just try it !!
do i plug it in
tell me what u got and i'll check
yes , plug it!!
and then when i plug it in am i useing the like equation form to come up with the answer
yes , exactly , except u only show the value of m & c ,
so itll be like 5=m(5)+3
no , m = 3 , use y = mx + c , to find c 5 = 3*5 + c , solve it
then put the value back in the eqn. with leaving x & y as variables
m=3 then you plug in the coordinates to x and y to find the b or y-intercept of the equation. Use the equation y=mx+b to find this. Then you have to turn that into standard form instead of point slope form.
so plug in the what to the coordinates
umm , u need the constant , first @ heat1017
i dont get it
use my eqn to get c then , i'll guide u
5 = 5*3 + c 5 = 15 + c c = 5-15 = -10 then y = mx + c y = 3x -10
What constant?
But standard form of the answer is 3x+y=-10
no , but then m = -3
Yes
then substitute -3 in the same eqn , u get ur answer
Standard form Ax+By=b Point-Slope Form y=mx+b
ok so what would be the answer then
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