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how do I factor completely z^2(x+1)-3z(x+1)-70(x+1)
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factor out the (x+1) \[(x+1)(z^2-3z-70)\]now factor the \[z^2-3z-70\]
ooooh. okay! thank you so much!
np
if i factor out the (x+1) dont i need to multiply it? or i just eliminate it.
no it needs to be there in the end (x+1)(z-10)(z+7)
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3a+2a+1a = a(3+2+1)
right right! now i got it. so once i factor \[z ^{2}-3z-70\] i just write it down next to it. okay, thanks! haha.
correct
Thankyouuu! :) have an awesome day!
same to you good sir
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