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Mathematics 9 Online
OpenStudy (anonymous):

−53>−3(3z+3)+3z

OpenStudy (austinl):

You need to distribute on the right side.

OpenStudy (anonymous):

What is the correct way to distribute

OpenStudy (austinl):

\(a(bx+c)=(ab)x+ac\) \(-3(3z+3)=(-3\times3)x+(-3\times3)\)

OpenStudy (anonymous):

What would be the second step?

OpenStudy (austinl):

Post what you have as an answer for the distribution. Then combine like terms :)

OpenStudy (anonymous):

I'm really struggling with the distribution because there's both positive and negative numbers

OpenStudy (austinl):

Two things. 1) Not the place for that 2) You're*

OpenStudy (anonymous):

−53>−3(3z+3)+3z

OpenStudy (austinl):

Ok, lets break it down. \(-3\times 3z=~?\) \(-3\times3=~?\)

OpenStudy (anonymous):

-9z and -9

OpenStudy (austinl):

Correct so now we have, \(-53>-9z+3z-9\) When you combine like terms, what do you get?

OpenStudy (anonymous):

I got it. It is 22/3.

OpenStudy (anonymous):

Thanks.

OpenStudy (austinl):

Correct!

OpenStudy (anonymous):

Thanks.

OpenStudy (austinl):

You are very welcome!

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