Question

Two airplanes leave an airport at the same
time. The velocity of the first airplane is
650 m/h at a heading of 60.5◦. The velocity
of the second is 560 m/h at a heading of 85◦.
How far apart are they after 2.9 h?
Answer in units of m

Answer 1

ok so this is a very long problem to work out

Answer 2

what you want to do is break the airplanes into their components of x and y using the angel given

Answer 3

angle*

Answer 4

after that do the delta x equations for each component

Answer 5

and the delta y for each component

Answer 6

of each plane

Answer 7

then you can use distance formula to determine how far apart they are

Answer 8

How do you break the airplanes into their components of x and y using the angle given?

Answer 9

so lets just do one plane so you can get the idea

Answer 10

Okay!

Answer 11

so that is a vector of the plane's speed

Answer 12

and see it's vector ends at some point (x,y) if you graphed it

Answer 13

so it is x distance from the airport and it is y distance from the airport and you can make that a triangle

Answer 14

so you can use trig rations like sin and cos to find the value of x and y to get point (x,y)

Answer 15

because the length of the hypotenuse is the speed of the aircraft and so you use either sin or cos to find the x and y parts