Two airplanes leave an airport at the same
time. The velocity of the first airplane is
650 m/h at a heading of 60.5◦. The velocity
of the second is 560 m/h at a heading of 85◦.
How far apart are they after 2.9 h?
Answer in units of m
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OpenStudy (anonymous):
Wasn't I just helping you with this?
OpenStudy (anonymous):
Yeah, there was a technical problem with my computer! Sorry!
OpenStudy (anonymous):
you can always go back to the original problem it is still open from what I can tell
OpenStudy (anonymous):
Thank you!
OpenStudy (anonymous):
do you understand it or do you still need help
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OpenStudy (anonymous):
I'm still a little confused
OpenStudy (anonymous):
!
OpenStudy (anonymous):
what are you confused about
OpenStudy (anonymous):
How to find the components, which is the first step to solve the problem
OpenStudy (anonymous):
do you know about sin cos and tan
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OpenStudy (anonymous):
Yes!
OpenStudy (anonymous):
Yes, I do!
OpenStudy (anonymous):
you know how they are used to find the sides of a triangle so the speed of the aircraft is the hypotenuse and the x component is the leg along the x axis and the y component is the leg parallel to the y axis
OpenStudy (anonymous):
|dw:1379455052330:dw|
OpenStudy (anonymous):
Yes, I understand!
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OpenStudy (anonymous):
I understand that!*
OpenStudy (anonymous):
ok so do you understand the rest of the problem now?