The Perimeter of a rectangle is 12m. Find the dimensions for which the diagonal is as short as possible.

Question

lilsis76 · Answer

@CarlosGP  This is my next question. |dw:1379458355526:dw|
WHen it says to find the dimensions for which the diagonal is as short as possible do I go ahead and divide it by 2 to get 6m. THen do I subtract the 6m... like this

x
6m-x

Again like the other problem?

anonymous · Answer

No, again try to solve using calculus. One side is: x and the other side is 6-x, agree?

lilsis76 · Answer

ya I agree. so it would look like this right? !

lilsis76 · Answer

x|dw:1379458642190:dw|

anonymous · Answer

What is the length of the diagonal ( HINT: Pythagoras Theorem)?

lilsis76 · Answer

Pathagorias theorem haha I cants spell it

anonymous · Answer

does this make sense to you?
$$D=\sqrt{x^2+(6-x)^2}$$

lilsis76 · Answer

okay $$a^2 + b^2 = c^2$$

anonymous · Answer

so c (I have named it D) a (for me is x) and b (for me is (6-x)) right?

lilsis76 · Answer

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