The sum of three times a number and a second number will total 12 or greater. The sum of three times the first number and twice the second number is less than or equal to 15. Find the two numbers.
A. first number = 2 and second number = -1
B. first number = 3 and second number = 2
C. first number = 5 and second number = 1
D. first number = 4 and second number = 1
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OpenStudy (anonymous):
Let us call our first number \(a\) and our second number \(w\). We know
\[3a+w\geq12\]
We also know:
\[3a+2w\leq15\]
So we need to solve these. Make sense?
OpenStudy (anonymous):
So it would be b if I plug in?
OpenStudy (anonymous):
Erm no, because let's say for the first one:
\[\eqalign{
&3(3)+(2)\ngeq12 \\
&9+2\ngeq12 \\
&11\ngeq12 \\
}\]
OpenStudy (anonymous):
Antoinette.
OpenStudy (anonymous):
Oh.
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OpenStudy (anonymous):
D?
OpenStudy (anonymous):
Yes.
OpenStudy (anonymous):
Yeah D!
OpenStudy (anonymous):
I plugged it in and that is what I think. Thank you!
OpenStudy (anonymous):
17.
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