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Mathematics
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factoring by grouping
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Are you going to post the expression you're trying to factor?
2a+b-6a^2-3ab
-6a^2 -3ab + 2a + b Factor the first two terms then the last two terms.
Thanx you
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Im stuck on factoring the last two terms
There's only one number that is common to the last two
Think about what happens when you try to factor prime numbers.
So it would be the same ?
Did you figure out the number yet?
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If i factor (2a+b) it would be the same because 1 is the greatest common factor
Okay so you factored out 1 from the last two terms
So now what?
I factor the first two terms and got -3a(2^2+b)?
-6a^2 -3ab + 2a + b = -3a(2a + b) + 1(2a + b) = (2a + b)(1 - 3a)
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thank you
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