Question

domain of the function f(x)= sqrt 11- x

Answer 1

since you cannot take the square root of a negative number, you job is to solve \(11-x\geq0\) for \(x\) which you do in one step by adding \(x\) to both sides

Answer 2

So would it have to be x is less than or equal to 11?
sincewe can't find the square root of a negative number?

Answer 3

I don't know how to do the less than or equal to sign on the computer. :)

Answer 4

yes, it would be \(x\leq 11\)

Answer 5

Wonderful! Thank you! So, in a similar problem how would I go about solving f(x)= sqrt x+4/ (x+2)(x-5) ?

Answer 6

I don't get how I would add x to both sides in this scenario... :(

Answer 7

You have to find all of the restrictions of x for f(x). There are several of them.

Answer 8

Found them a couple of minutes ago! -4, -2, and 5, right?

Answer 9

I think!

Answer 10

Well, I think you should express it more completely.

\(x \nless -4\)
\(x \ne -2\)
\(x \ne 5\)

Answer 11

i think you should say that it is \(x>-4\) rather than \(x\nless -4\) but whatever

Answer 12

I was thinking in terms of what x cannot be @satellite73

Answer 13

that's why you see not less than and not equal

Answer 14

it is a not uncloudy day

Answer 15

No, I was expressing the restrictions on x.

Answer 16

It's not obstruse

Answer 17

@satellite73 you sort of came in at the end and didn't get the full conversation. I specifically mentioned that it was necessary to find the restrictions on x.

Answer 18

i'm just funnin