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Mathematics 10 Online
OpenStudy (anonymous):

|4x - 3| - 1 > 12?

OpenStudy (anonymous):

Hey. I'll try to solve this one... I think I remember this.

OpenStudy (anonymous):

Yea. Get the absolute value alone. So add 1 to both sides... Or wait... make 2 equations first.... or... lol.

OpenStudy (anonymous):

I think you get it alone first. |4x-3| > 13. Yea. Then make two equations, dropping the bars. 4x-3 > 13 and then flip and negate, 4x-3<-13.

OpenStudy (anonymous):

Now you just solve.

OpenStudy (anonymous):

x>5/2 and x<-4. If you have to graph it...

OpenStudy (anonymous):

Wait you do that solution set thing first. {x<-4 V x>5/2} Now graph... <=====O------------O=====> (Open circles, shade outwards.) -4 5/2

OpenStudy (anonymous):

My brain (Kaboom)

OpenStudy (anonymous):

Mine too. My brain is dead atm from trying to do my pre-calc hw.... so...

OpenStudy (anonymous):

Thanks for the answer though, I will use this as a sort of "guide" for future questions. New fan.

OpenStudy (anonymous):

Lol. I'll try to explain it simple quick. 1. Get the bars alone. 2. Drop the bars, make 2 equations. One as is, the other, flip the sign and negate the right side. 3. Solve algebraically. 4. Make a solution set and graph.

OpenStudy (anonymous):

Also this is all wrong I forgot to make the 3 positive... XD

OpenStudy (anonymous):

O__________________________________0

OpenStudy (anonymous):

x > -2.5 or x > 4 Should be the answer right........?

OpenStudy (anonymous):

Its x>4 x<-4....

OpenStudy (anonymous):

So... {x<-4 V x>4} <====O--------O====>

OpenStudy (anonymous):

With -4 on the first O and 4 on the 2nd O.

OpenStudy (anonymous):

So

OpenStudy (anonymous):

x < -4 or x > 4

OpenStudy (anonymous):

Yes.

OpenStudy (anonymous):

WOO

OpenStudy (anonymous):

Figured it out. Thanks so much

OpenStudy (anonymous):

No prob.

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