|4x - 3| - 1 > 12?
Hey. I'll try to solve this one... I think I remember this.
Yea. Get the absolute value alone. So add 1 to both sides... Or wait... make 2 equations first.... or... lol.
I think you get it alone first. |4x-3| > 13. Yea. Then make two equations, dropping the bars. 4x-3 > 13 and then flip and negate, 4x-3<-13.
Now you just solve.
x>5/2 and x<-4. If you have to graph it...
Wait you do that solution set thing first. {x<-4 V x>5/2} Now graph... <=====O------------O=====> (Open circles, shade outwards.) -4 5/2
My brain (Kaboom)
Mine too. My brain is dead atm from trying to do my pre-calc hw.... so...
Thanks for the answer though, I will use this as a sort of "guide" for future questions. New fan.
Lol. I'll try to explain it simple quick. 1. Get the bars alone. 2. Drop the bars, make 2 equations. One as is, the other, flip the sign and negate the right side. 3. Solve algebraically. 4. Make a solution set and graph.
Also this is all wrong I forgot to make the 3 positive... XD
O__________________________________0
x > -2.5 or x > 4 Should be the answer right........?
Its x>4 x<-4....
So... {x<-4 V x>4} <====O--------O====>
With -4 on the first O and 4 on the 2nd O.
So
x < -4 or x > 4
Yes.
WOO
Figured it out. Thanks so much
No prob.
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