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Mathematics 18 Online
OpenStudy (anonymous):

A quality control inspector is in charge of inspecting drill bits that are produced on an assembly line. The diameter of a drill bit can be modeled by the equation |x − 0.525| = 0.01. Show your work in solving the eqation to determine the minimum and maximum diameters of the drill bits.

OpenStudy (ybarrap):

So, let's use other numbers so you can do this problem: |x - .5| = .1 is the same as |x - .5| <= .1 which is the same as |x - .5| <= .1 which is the same as -.1 <= x - .5 <= .1 which is -.1 + .5 <= x <= .1 + .5 same as .4 <= x <= .6 So in words: As the minimum that the diameter can be is .4 and the maximum that it can be is .6. Substitute your values to come up with similar results.

OpenStudy (anonymous):

Please i need help

OpenStudy (anonymous):

"is the same as |x - .5| <= .1" explain please

OpenStudy (ybarrap):

If the maximum that some thing can be is .1 then certainly it can be less than that. Do you agree?

OpenStudy (anonymous):

yes

OpenStudy (ybarrap):

This equation is giving us a tolerance. |x - .5| is the maximumum allowed tolerance from the "desired" value of ".5". This tolerance is .1. Tolerance is an indication of what you wil tolerate as a control engineer. If this "play" around the drill bits diameter is greater than .1 then that is a problem if it is less than or equal to .1 then everything is good.

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