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Mathematics 16 Online
OpenStudy (anonymous):

Is b a linear combination of the columns A?

OpenStudy (anonymous):

\[A= \left[\begin{matrix}1 & -1&2&1 \\ 2&-3&2&0\\-1&1&2&3\\-3&2&0&3\end{matrix}\right]\] b=\[\left(\begin{matrix}2 \\ 3\\6\\9\end{matrix}\right)\]

OpenStudy (anonymous):

Do I go about solving Ax=b??

ganeshie8 (ganeshie8):

that wud be a long process

ganeshie8 (ganeshie8):

observe that, last column = 3rd column - 1st column

OpenStudy (anonymous):

But what does that mean?

ganeshie8 (ganeshie8):

let me think a bit... wat that means

ganeshie8 (ganeshie8):

it wont tell us much, i think we need to reduce the augmented matrix, and see if it has a solution

ganeshie8 (ganeshie8):

augmented matrix \[ \left[\begin{matrix}1 & -1&2&1&2 \\ 2&-3&2&0&3\\-1&1&2&3&6\\-3&2&0&3&9 \end{matrix}\right] \]

OpenStudy (tkhunny):

The words "Reduced Row Echelon Form" should come to mind. Don't panic when a row disappears! It will be okay. Just keep going.

OpenStudy (anonymous):

None of my rows disappeared! now I'm worried @tkhunny

ganeshie8 (ganeshie8):

that means the system is consistent, and we have solution. So it is possible to write b as linear combination of column vectors of A

OpenStudy (anonymous):

Oh! So if I did have a row of zeros there would be a variable and b would not be a linear combination?

ganeshie8 (ganeshie8):

if u have all 0's, we can still have solutions (infinite) but if we have a row like : 0 0 0 0 8 then its impossible to get a 8 out of 0s -- so we wont be having any solution. and we say the system is inconsistent

ganeshie8 (ganeshie8):

since the matrix we have has det=0, there will be some verctors, b, which we cant reach. let me quickly cook up some b, for which its not possible to linearly combine column vectors

OpenStudy (anonymous):

oh ok!

ganeshie8 (ganeshie8):

below b cannot be linearly combined using our matrix column vectors, try and see :) b = \(\left(\begin{matrix}2 \\ 3\\6\\7\end{matrix}\right) \)

OpenStudy (anonymous):

Wait I don't see why, all that does is change one numbe

ganeshie8 (ganeshie8):

yes, wid that change in number, u will not have all 0's in ur last row in augmented matrix

OpenStudy (anonymous):

Okay I got to go back and do it because mine looked nothing like that haha. But for now I'm going to get some sleep, thanks for your help!

ganeshie8 (ganeshie8):

np :) have good sleep... trust wolfram... this is big matrix, manually doing is a pain !

OpenStudy (tkhunny):

The reduced row echelon form takes skill and care. You cannot hurry through it. Don't be afraid to write the WHOLE MATRIX at each stage.

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