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Mathematics 9 Online
OpenStudy (anonymous):

please look below for problem

OpenStudy (anonymous):

|dw:1379550777130:dw|

OpenStudy (john_es):

Do you need the angle?

OpenStudy (anonymous):

|dw:1379550887879:dw|

OpenStudy (john_es):

And you need Vx and Vi? Is this is the case, then you can use the relations, \[\tan 63=\frac{16.12}{Vxi}\]Then, when you know the value of Vxi, you can calculate the valur of Vi, using Pitagorean theorem, \[\sqrt{16.12^2+Vxi^2}=Vi\]

OpenStudy (anonymous):

is the value of vx 94.96

OpenStudy (john_es):

The value I obtain for the variable Vxi you draw is \[Vxi=\frac{16.12}{\tan(63)}\]

OpenStudy (john_es):

That is, 8.21.

OpenStudy (anonymous):

oh my calculator wasnt on degree

OpenStudy (john_es):

This is then, the problem. :)

OpenStudy (anonymous):

the answer is 18.09

OpenStudy (john_es):

Perfect ;)

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