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Mathematics 23 Online
OpenStudy (anonymous):

Which trig factor should i use on this triangle? HELP PLEASE

OpenStudy (anonymous):

|dw:1379562923690:dw|

zepdrix (zepdrix):

oo cool hair c:

OpenStudy (anonymous):

Thanks man, can you help me?

zepdrix (zepdrix):

So to solve for x, we want to relate the side `opposite` and the side `adjacent` to our angle 35 degrees.

zepdrix (zepdrix):

Which trig function deals with `Opp` and `Adj`? :o

OpenStudy (anonymous):

tangent?

zepdrix (zepdrix):

Yesss, good good good.

zepdrix (zepdrix):

Understand how to set it up?

OpenStudy (anonymous):

35tan(12 ?

zepdrix (zepdrix):

The tangent of our angle is equivalent to the ratio of the opposite side to the adjacent side. \[\Large \tan \theta\quad=\quad \frac{opp}{adj}\] Looks like in this case, our setup will be,\[\Large \tan35^o\quad=\quad\frac{x}{12}\] Understand how I came to that setup? :O

OpenStudy (anonymous):

Yes :0 because x is opposite of the angle and 12 is the adjacent leg

zepdrix (zepdrix):

cool. So how do we solve for x now? Hmm..

OpenStudy (anonymous):

move x to the other side and use a calculator ;D

zepdrix (zepdrix):

no no no careful! \:D/ move 12 to the other side! but ya, calculator to finish it up seems good :3

OpenStudy (anonymous):

damn so 35 tan times 12

zepdrix (zepdrix):

I'm not sure what 35 tan means. That's kind of a sloppy way to write that. Try to get used to saying tan35 times 12 instead. I think that's what you meant at least. :)

OpenStudy (anonymous):

i keep getting negative numbers.

zepdrix (zepdrix):

Hmm is your calculator in `Degree Mode` ?

OpenStudy (anonymous):

im not sure its just the calculator on my boyfriends phone :/

zepdrix (zepdrix):

oh boy you silly billy +_+ maybe google has a calculator you can use, hmm lemme think.

zepdrix (zepdrix):

ya do a google search for calculator, the google calculator has a radians/degree switch :D

OpenStudy (anonymous):

Lol im just trying to cram cause im moving tomorrow morning and i just wanna finish this lol

OpenStudy (anonymous):

\[ 12\tan(35^\circ)=\dots \]

OpenStudy (anonymous):

http://www.wolframalpha.com/input/?i=12+tan+35

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