Which trig factor should i use on this triangle? HELP PLEASE
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oo cool hair c:
Thanks man, can you help me?
So to solve for x, we want to relate the side `opposite` and the side `adjacent` to our angle 35 degrees.
Which trig function deals with `Opp` and `Adj`? :o
tangent?
Yesss, good good good.
Understand how to set it up?
35tan(12 ?
The tangent of our angle is equivalent to the ratio of the opposite side to the adjacent side. \[\Large \tan \theta\quad=\quad \frac{opp}{adj}\] Looks like in this case, our setup will be,\[\Large \tan35^o\quad=\quad\frac{x}{12}\] Understand how I came to that setup? :O
Yes :0 because x is opposite of the angle and 12 is the adjacent leg
cool. So how do we solve for x now? Hmm..
move x to the other side and use a calculator ;D
no no no careful! \:D/ move 12 to the other side! but ya, calculator to finish it up seems good :3
damn so 35 tan times 12
I'm not sure what 35 tan means. That's kind of a sloppy way to write that. Try to get used to saying tan35 times 12 instead. I think that's what you meant at least. :)
i keep getting negative numbers.
Hmm is your calculator in `Degree Mode` ?
im not sure its just the calculator on my boyfriends phone :/
oh boy you silly billy +_+ maybe google has a calculator you can use, hmm lemme think.
ya do a google search for calculator, the google calculator has a radians/degree switch :D
Lol im just trying to cram cause im moving tomorrow morning and i just wanna finish this lol
\[ 12\tan(35^\circ)=\dots \]
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