Mathematics
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OpenStudy (anonymous):
Divide: (7 + 4i) ÷ (2 + 3i)
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hartnn (hartnn):
multiply and divide by the conjugate of the denominator
you know whats the conjugate of 2+3i ?
OpenStudy (anonymous):
2+3i?
OpenStudy (anonymous):
right?
hartnn (hartnn):
the conjugate of a+bi will be a-bi
what about 2+3i ?
OpenStudy (anonymous):
i d k??
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hartnn (hartnn):
just flip the sign of imaginary part!
conjugate of 2+3i is 2-3i
ok ?
OpenStudy (anonymous):
oooohhh i get it you just flipped the sign
hartnn (hartnn):
yes, now multiply and divide that , what u get ?
OpenStudy (anonymous):
i
OpenStudy (anonymous):
?
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OpenStudy (anonymous):
imm sorry i dk what i am doing
hartnn (hartnn):
do this: \(\large \dfrac{(7+4i)(2+3i)}{(2+3i)(2-3i)}\)
you can multiply, right ? :P
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
do i use the foil method
hartnn (hartnn):
sorry, a typo, do this ***
\(\large \dfrac{(7+4i)(2-3i)}{(2+3i)(2-3i)}\)
yes, exactly, the foil ! in numerator and denominator both
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OpenStudy (anonymous):
ok i got -12i^2-13i+14/9i^2+4
hartnn (hartnn):
numerator is absolutely correct! good
the denominator should have -9i^2+4, right ??
OpenStudy (anonymous):
no -9i^-12i+4 i forgot to add -6i+-6i
hartnn (hartnn):
-6i+6i should be there, check again ?
and that = 0
OpenStudy (anonymous):
ohhh ok i get it
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hartnn (hartnn):
cool, now whats i^2 = .... ?
you know ?
OpenStudy (anonymous):
no
OpenStudy (anonymous):
is it an imaginary number
hartnn (hartnn):
this question belongs o imaginary nu,mber topic, right ?
OpenStudy (anonymous):
yes
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OpenStudy (anonymous):
so what do i do after that
hartnn (hartnn):
so, \(i=\sqrt{-1}\)
square both sides of this, what u get ?
OpenStudy (anonymous):
√-12i+1?
OpenStudy (anonymous):
on the numerator
hartnn (hartnn):
what ??
just square both sides of \(i=\sqrt{-1}\)
so that we get the value of i^2
which we will substitute in the expression you got....