Question

Can someone give me the answer?
I can't get this wrong!

The leaning tower of Pisa is about 56 meters tall. A ball released from the top takes 3.4 seconds to reach the ground. The final velocity of the ball before it hits the ground is 33 meters/second. Assuming that the ball experienced a constant acceleration throughout this descent, calculate the magnitude of the acceleration.

a) 9.8 meters/second^2
b) 9.7 meters/second^2
c) 112.2 meters/second^2
d) 0.10 meters/second^2

Answer 1

\[d=\frac{1}{2}gt^2\]Solve this for g:\[g=\frac{2d}{t^2}\]Plug in values:\[g=\frac{2(56m)}{(3.4s)^2)}=?\]

Answer 2

That's one way...

Answer 3

if we ignore the air drag, acceleration is always g.

Answer 4

So it's B?

Answer 5

It's B based on the calculations. In reality, you should end up with values that calculate out to about 9.81 m/s^2.

Answer 6

The teacher is probably wanting to see if you actually calculated it out based on the given values.

Answer 7

Well it's an online class and I just have to answer the questions.

Answer 8

Then mark B and move on :)

Answer 9

I have one last question on measures of motion, I think I know the answer but I want to make sure, can you help me?

Answer 10

Go ahead and post it