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Mathematics 16 Online
OpenStudy (anonymous):

help use pythagorean theorem to find the value of x

OpenStudy (anonymous):

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OpenStudy (anonymous):

Pythagorean Theorem: a^2 + b^2 = c^2, where c is always the hypotenuse [longest side] so we have: \[4^2+h^2=5^2\] solve for h

OpenStudy (anonymous):

Does h = 1

OpenStudy (anonymous):

Sorry does it equal 18

OpenStudy (anonymous):

sorry it equals 16

OpenStudy (zpupster):

25 - 16 = h^2 sqrt 9 = h

OpenStudy (anonymous):

\[4^2 + h^2 = 5^2\]\[16 + h^2 = 25\]\[h^2 = 25-16\]\[h = \sqrt{9} = 3\]

OpenStudy (anonymous):

sorry thank you

OpenStudy (zpupster):

this is a famous 3-4-5 triangle, you will see this a lot

OpenStudy (anonymous):

Ok

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