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If f(x) = sqrt(x), sketch and label the locator point of 2-f(x-2).
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they want you to graph:\[f(x) = 2 - \sqrt{x-2}\]
How can I find the locator point from that equation?
locator point is the point by which the standard function is deviated. this function is deviated from sqrt(x) 2 units to the right and 2 up. so instead of the locator point being (0, 0) it is (2, 2)
I see! Thank you!
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