Question

Using the Quadratics Formula

Answer 1

\[2x ^{2}+7x+3=40\]

Answer 2

You have to first put it in the form:

\(\Large ax^2+bx+c=0\)

So just subtract the 40 from both sides.

Then plug a, b and c into the QF:
\[\Large x=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\]

Answer 3

\[\frac{ x= -7 \pm \sqrt{7^{2}-4 X2X-37} }{ 4 }\]

Answer 4

I think what you mean there is:

\(\Large x=\dfrac{ -7 \pm \sqrt{7^{2}-4 (2)(-37)} }{ 4 }\) right??

If so, then yes, that is correct so far.