Find dy/dx.
\[y=\pi ^{3}\] I got 3\[3\pi ^{2}\] as an answer but solutions manual tells me answer is zero? :/
\(\pi\) is a constant. You're not trying to find \(\dfrac{dy}{d\pi}\)
The answer is 0 because π is a number and not a variable such as x, where dy/dx of x would be 1.
that makes sense! thank you both! @tkhunny @juststoper How would I find \[f \prime(x)=x ^{\pi}+\frac{ 1 }{ x ^{\sqrt{10}} }\] the solutions say the answer is \[\pi x ^{\pi-1}-\frac{ \sqrt{10} }{ x ^{1+\sqrt{10}} }\] I understand how they got the first part but don't understand the fractional part
\(\dfrac{d}{dx}x^{-\sqrt{10}} = -\sqrt{10}x^{-\sqrt{10} - 1}\)
Hm okay! but how would the exponent on x turn to \[1+\sqrt{10}\]?
\(\dfrac{1}{a^{b}} = a^{-b}\)
I get it now. At least I think I do! Thank you very much! :)
The WHOLE trouble with the problem is the ugly numbers. Would you even have struggled with \(\dfrac{1}{x^{2}}\)? I doubt it. Don't let ugly numbers scare you.
your right thats what got me I saw it and just got so confused -_- Thank you again for your help! I appreciate it
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