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What is the molarity of a 5.00x10^2 mL solution containing 21.1 g of potassium bromide (KBr)? The molar mass of KBr is 119.0 g/mol.
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\[a) 3.55 x 10^-4 M\] \[b) 42.2M\] c) 0.355 M\[d)8.87*10^{-2}\]
5*10^2 ml = 500 ml = 0.5 liter convert 21.1 g of KBr to mol by dividing the mass by the molar mass then calculate how many moles per liter you have.
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