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Mathematics 15 Online
OpenStudy (anonymous):

Can someone help me with this I'm so lost >:(

OpenStudy (anonymous):

terenzreignz (terenzreignz):

There's a little something called... the Pythagorean Theorem... ;)

OpenStudy (yttrium):

I think you can solve this by using the formula A = absin(90)/2

OpenStudy (yttrium):

I mean, A = [(AB)(BC)sin90]/2

OpenStudy (anonymous):

Uhh I'ma need help with that lol

OpenStudy (yttrium):

Just substitute the given. It's like A = (21*72sin90)/2

terenzreignz (terenzreignz):

There's no need to jump to 'trigonometric' conclusions.... For any right triangle, the longest side c is always given by \[\Large c = \sqrt{a^2 + b^2} \] where a and b are the two other sides. And @Yttrium don't you think sin90 is... redundant? ;)

OpenStudy (yttrium):

OMG. HAHAHA. I thought find the area of the triangle. LALALALA!

OpenStudy (anonymous):

Ohh lord @Yttrium you gon make me fail lol

OpenStudy (yttrium):

\[BC = \sqrt{AB^2 +AC^2 }\] Just substitute the value, and you can now solve for C. hahahaha. I'm so sorry, I really though it was for area. hahaha. Maybe an effect of too much hunger. :D

terenzreignz (terenzreignz):

Lord Yttrium? That's a laugh :/ And yes @Yttrium that's what we needed :/

OpenStudy (yttrium):

@terenzreignz , I know I'm stupid. And you're the one to be called a Lord.

terenzreignz (terenzreignz):

No... I'm not... @ Lord Yttrium... *Master* Terence is more like it XD anyway @torontoXO you have your answer yet? :D Just add the squares of the two given sides and THEN take its square root, it's easy! :D

OpenStudy (anonymous):

I'ma do that now lol

terenzreignz (terenzreignz):

Yes... I'll wait :)

OpenStudy (yttrium):

It's okay to call @yttrium for me. I'm still willing to help. :)

OpenStudy (anonymous):

75?

OpenStudy (yttrium):

Got it. :)

OpenStudy (anonymous):

Swagg

terenzreignz (terenzreignz):

Awesome :)

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