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Mathematics 7 Online
OpenStudy (anonymous):

for the function f(x) = sqrt(8x + 10) find the inverse function

OpenStudy (anonymous):

I think its (x^2-10)/8, x is less than or equal to 0

hartnn (hartnn):

(x^2-10)/8 is absolutely correct! how did u come up with x is less than or equal to 0 ?

OpenStudy (anonymous):

I wasnt sure of that part

hartnn (hartnn):

ok, can you find the domain of the function ?

hartnn (hartnn):

and range of a function ?

hartnn (hartnn):

range of f(x) is f(x)>= 0 , right ?? because sqrt alwys gives non-negative answer. got this ?

OpenStudy (anonymous):

Domain is x is greater than or equal to -(5/4)?

hartnn (hartnn):

yup

hartnn (hartnn):

but the range is of significance in this question, because 'Domain of INVERSE function = Range of original function' and vice versa remember this

hartnn (hartnn):

so u got how range of f(x) is f(x) > = 0 ?

OpenStudy (anonymous):

yeah

hartnn (hartnn):

that means domain of inverse function will be x>= 0 so, its (x^2-10)/8, x is greater than or equal to 0 :)

OpenStudy (anonymous):

ok that makes sense. so for f(x) = -5sqrt(x) - 3. It would be (x+3)^2/25, x is less than or equal to -3, because the domain of f is x is less than or equal to 3. right?

OpenStudy (anonymous):

i meant the range of f is x is less than or equal to 3

hartnn (hartnn):

correct!

OpenStudy (anonymous):

Thank you!

hartnn (hartnn):

welcome ^_^

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