Question

Solve the equation by factoring
2x-17 = 9/x

Answer 1

\(\large 2x-17 = \frac{9}{x} \)

Answer 2

start by multiplying the x thru out the eq'n

Answer 3

\(\large x \times (2x-17 ) = x \times \frac{9}{x} \)

Answer 4

ok

Answer 5

simplfy a bit, wat do u get

Answer 6

Can you show me, I'm not sure

Answer 7

alright

\(\large 2x^2-17x = 9 \)

\(\large 2x^2-17x - 9 = 0 \)

Answer 8

u knw how to factor this ? :)

Answer 9

I need my memory refreshed

Answer 10

Hello?

Answer 11

wat grade u in ?

Answer 12

I am taking College Algebra...I haven't used algebra in a long time

Answer 13

ohk

Answer 14

check this out
http://www.purplemath.com/modules/solvquad.htm

Answer 15

u may ask me if u get any questions going thru that...

Answer 16

Thanks for the link. I am still stuck on 2x^2 -17x-9 =0 Can you show me how to factor this part please?

Answer 17

u went thru the link ?

Answer 18

I want to get a factor that equals 17 and - 9?

Answer 19

you're in right direction :)

Answer 20

basically we need to find two numbers :-
1) whose product equals 2x-9 = -18
2) whose sum equals -17

Answer 21

can u find them ?

Answer 22

observe that -18 and 1 will satisfy above

Answer 23

2x^2 -17x-9 =0

2x^2 -18x + 1x-9 =0

Answer 24

now factor first two terms, and last two terms

Answer 25

2x^2 -17x-9 =0

2x^2 -18x + 1x-9 =0

2x(x-9) + 1(x-9) = 0

Answer 26

notice that we can pull out (x-9)

Answer 27

yes

Answer 28

2x^2 -17x-9 =0

2x^2 -18x + 1x-9 =0

2x(x-9) + 1(x-9) = 0

(x-9)(2x+1) = 0

Answer 29

next, use zero product property

Answer 30

2x^2 -17x-9 =0

2x^2 -18x + 1x-9 =0

2x(x-9) + 1(x-9) = 0

(x-9)(2x+1) = 0

x-9 = 0, 2x+1 = 0

x = 9 , x = -1/2

Answer 31

see if that makes more or less sense :)

Answer 32

Yes, the last part I remember how to do. The factoring part is where I get confused at. Thanks so much for your help!

Answer 33

np :)
just u have do few problems until u get confidence i guess... good luck !

Answer 34

Thanks :)