Solve the system by graphing? Help? :(

Question

abb0t · Answer

What system?

anonymous · Answer

this one. Im not sure how to do it?

anonymous · Answer

draw both lines.. the point of intersection is solution

abb0t · Answer

Rearrange it into equation of a $line$: $\sf \color{red}{y=mx+b}$

abb0t · Answer

m = slope
b = shifted $\uparrow$ or $\downarrow$ by "y" units.

anonymous · Answer

Idk if i did it write but y=-3x - 10 and the other one is y =1x-2

abb0t · Answer

a negative slope looks like this: $\large \. $ and a positive sloe: $\large /$ on the origin.

abb0t · Answer

NOW, it looks as if on the first one, you shifted the line DOWN by 10 and the second one DOWN by 2. try it.

anonymous · Answer

none of my answers look like the other answers :/

anonymous · Answer

the best way to plot lines in graph is to use intercept form..

x/a  +y/b=1

anonymous · Answer

in your case 4x-4y=8 will transform to 

x/2  + y/(-2) =1

so x intercept = 2 and y intercept =-2

i.e points are (2.0) and (0.-2)

so you can plot a line using two points..

anonymous · Answer

similarly plot the other lline.. and find the point of intersection

and bingo you get the solution

anonymous · Answer

well how did you get that equation? bc i tried doing that and i got something way different

anonymous · Answer

divide both side of eqn by 8...


actually your aim is to bring 1 on R.H.S of eqn..