calculate d/dx
Ok whats the equation
y=3x+9/8x-1
the derivative for those are 3 and 8 but what do I use to solve it? Product rule? Quotient rule?
You have to use the quotient rule
That would be the quotient rule
So \[\frac{ f'(x)g(x)-f(x)g'(x) }{ g(x)^2 }\]
ok so i got the answer 48x+69/128x-16 but my online hw is saying that it is incorrect
Well lets break it down further: We know that d/dx is \[\frac{ (3)(8x-1)-(3x+9)(8) }{ (8x-1)^2 }\] So just simplify it: \[\frac{ 24x-3-24x-72 }{ (8x-1)^2 }\] Notice how I distributed the minus sign in -(24x-72)
Sorry on the last statement I ment distributin gthe minus sign -(24x +72)
thanks man I really appreciate it! My professor gives us no notes for reference and the book is about useful as a poopy flavored lollipop...
as*
Lol I hear you. I'm struggling with calculus to and no problem anytime :D
Are you a college student? haha
Yes
Nice where at? I'm at Arizona State
University of Houston
Main campus
Right on man! what is your major?
I want to be in computer science but they put me as undecided for some odd reason. wbu?
Business Communication I'm getting my business degree to have something to fall back on but I want to go into Broadcasting
Oh so in the media or radio buisness
Nice
most likely media
I do video editing and all that stuff for a hobby actually. I was in a class in high school and I loved it
This is one of my videos I did with a friend
I'm so jealous of that i've always wanted to get into video editing I've just never had the tools to try it xD
Their are ways you can get programs for free but mostly it doesn't work. Since your a college student you can get discounts on things like adobe premier or if your on a mac final cut pro
Though I warn you that you need a good computer to run these programs
That was a pretty engaging short haha i like the concept
lol
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