how do you factor by grouping
Usually, factoring by grouping is used to factor a 4-term polynomial. You factor a common factor out of the first two terms, and you factor a common factor out of the last two terms. Then you factor out a common factor.
If you have a problem to do, post it, and we'll do it together.
2c^4-8c^3+18c^2-72c
The first rule of factoring is to always try to factor a common factor first. Can you factor a common factor out of all terms?
I think -8c^3 & -72c
No. Factoring a common factor out of all terms is done by looking at all terms, both the coefficients (the numbers) and the variables, and seeing if they have a common factor. Let's start with the coefficients. What is the GCD of 2, -8, 18, and -72? What is the largest number all those numbers are divisible by?
2
Great. Now let's look at the variables: What is the GCF of \(c^4, ~c^3, ~c^2, ~c\) ?
1
How about c? Every one of those is divisible by c, isn't it?
We're not looking at the number parts; we are now looking at the variable parts.
yeah
That means the GCF for the entire polynomial is 2c. Now we factor out 2c out of the whole thing.
\(2c^4-8c^3+18c^2-72c\) \( = 2c(c^3 - 4c^2+9c - 36) \) You follow?
yeah .
Ok, now we start with the factoring by grouping part. Inside the parentheses, can you factor a common term out of \(c^3\) and \(-4c^2\)? Also, inside the parentheses, can you factor a common term out of \(9c\) and \(-72c\)?
Remember, this factoring is similar to what we did before. Take out the largest number you can, and take out the largest variable part you can.
okay I will be taking out c^3 and -72c?
No and no. Let's do it piece by piece. What do the terms \(c^3\) and \(-4c^2\) have in comon?
the same varibles
c^3 is made up of 3 c's. c^2 is made up of 2 c's. How many c's do they have in common?
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