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Mathematics 9 Online
OpenStudy (jenniferjuice):

please help? ツ (i have a couple of questions i need help with)

OpenStudy (jenniferjuice):

Which expression is the simplified form of the square root of r to the thirty-third power.? r^11 r^16 r^11 the square root of r. r^16 the square root of r.

OpenStudy (anonymous):

I would say the last one:)

OpenStudy (anonymous):

because 2 goes in 33 i think 16 times and it comes out with the remainder of 1. So, r^16 is on the outer part. and the radical r stays inside

OpenStudy (jenniferjuice):

oh i see thanks ツ :D

OpenStudy (anonymous):

No problem:)

OpenStudy (jenniferjuice):

i have a couple more questions ...could you help me with them?

OpenStudy (anonymous):

I will do my best t o help you:)

OpenStudy (anonymous):

***to

OpenStudy (jenniferjuice):

What is the exact value of the expression the square root of 16 times y to the sixth power. + 9the square root of y to the eighth power. − 3the square root of y to the sixth power. − the square root of y to the eighth power.? Simplify if possible. y3 + 8y4 9y2 13y3 + 2y4 9y7

OpenStudy (jenniferjuice):

idk if you can understand that so im going to post a screen shot

OpenStudy (jenniferjuice):

OpenStudy (anonymous):

Ok thats better lol. Let me take a moment to figure this out:)

OpenStudy (anonymous):

y3 +8y4 is my answer.

OpenStudy (jenniferjuice):

lol thanks

OpenStudy (anonymous):

because you keep the 3rd and forth terms in its original state

OpenStudy (anonymous):

and your very welcome:)

OpenStudy (jenniferjuice):

:D

OpenStudy (anonymous):

Is that your last one?

OpenStudy (jenniferjuice):

no but i was wondering how you solve these .. cause im going to get more in the future and i want to be able to solve it

OpenStudy (anonymous):

Ok hold on a minute. let me work it out. and ill put the steps up.

OpenStudy (jenniferjuice):

thankyou :)

OpenStudy (anonymous):

to remove the sqrt we first give the entire equation the power of 1/2 (567w^12)^1/2 567^1/2*(w^12)^1/2 we convert 567 back into sqrt by removing the power w^6sqrt567 w^6sqrt9*9*7 9w^6sqrt7 so option A is the answer

OpenStudy (anonymous):

I hope that makes sense

OpenStudy (anonymous):

By the way is that you in your pic? lol

OpenStudy (jenniferjuice):

nope..lol its kellin quinn

OpenStudy (anonymous):

Oh lol. Well, i hope you understood the concepts:)

OpenStudy (jenniferjuice):

yeah thanks it really helped :)

OpenStudy (anonymous):

Im glad. If you neeed help with anything, let me know:)

OpenStudy (jenniferjuice):

okay! :D

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