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\((f+3g)(2) = f(2) + 3\cdot g(2)\)
You're given f, and you're given g, so just evaluate f(2), and g(2), and then add the first result to 3 times the second.
Do what?
You have: \(f(x)=4x-5\) So, what is \(f(2)\)?
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\(g(x)=(x+3)^2\) So, what is \(g(2)\)?
\[f(2) = 3?\]
yes. Once you have those two results, just plug them in to: \((f+3g)(2) = f(2) + 3\cdot g(2)\)
\[g(2) = 31\] for the second one
so its 3 + 3 X 31?
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whoa... how did you get g(2) = 31?
25* sorry
Right. So now \((f+3g)(2) = f(2) + 3\cdot g(2)= 3 + 3\cdot 25=?\)
78!
right :)
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awesome:DD Thank you so much! SO much less complicated than it seems <3
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