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Mathematics 13 Online
OpenStudy (lifeisadangerousgame):

Help with understanding what the question wants?

OpenStudy (lifeisadangerousgame):

OpenStudy (debbieg):

\((f+3g)(2) = f(2) + 3\cdot g(2)\)

OpenStudy (debbieg):

You're given f, and you're given g, so just evaluate f(2), and g(2), and then add the first result to 3 times the second.

OpenStudy (lifeisadangerousgame):

Do what?

OpenStudy (debbieg):

You have: \(f(x)=4x-5\) So, what is \(f(2)\)?

OpenStudy (debbieg):

\(g(x)=(x+3)^2\) So, what is \(g(2)\)?

OpenStudy (lifeisadangerousgame):

\[f(2) = 3?\]

OpenStudy (debbieg):

yes. Once you have those two results, just plug them in to: \((f+3g)(2) = f(2) + 3\cdot g(2)\)

OpenStudy (lifeisadangerousgame):

\[g(2) = 31\] for the second one

OpenStudy (lifeisadangerousgame):

so its 3 + 3 X 31?

OpenStudy (debbieg):

whoa... how did you get g(2) = 31?

OpenStudy (lifeisadangerousgame):

25* sorry

OpenStudy (debbieg):

Right. So now \((f+3g)(2) = f(2) + 3\cdot g(2)= 3 + 3\cdot 25=?\)

OpenStudy (lifeisadangerousgame):

78!

OpenStudy (debbieg):

right :)

OpenStudy (lifeisadangerousgame):

awesome:DD Thank you so much! SO much less complicated than it seems <3

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