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Trigonometry
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find sec[sin^-1(3/5)] in radians
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sec=1/cos sin^2 x+cos^2 x=1
Ok, but I do not see where that is taking me.
oh, that's an arcsine isn't it...
yes.
this is cheating basically, but wiki lists some arctrig function identities...
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I'll check it out!
http://en.wikipedia.org/wiki/List_of_trigonometric_identities#Inverse_trigonometric_functions
so you're taking the cosine of an arcsine and finding the reciprocal
Indeed
=\(\Huge\frac{1}{\sqrt{1-x^2}}\) according to wikipedia
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1/((1-(3/5)^2)^-1)
^-2 instead of ^-1
yeh I guess
1.25
and 5pi/4?
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shrugs, use wolfram alpha to check your work hehe
lol
thanks
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