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Mathematics 17 Online
OpenStudy (anonymous):

Solve the inequality and express your answer in interval notation.

OpenStudy (anonymous):

\[x ^{2}+6x+7<0\]0

OpenStudy (***[isuru]***):

Hi, r u sure that the expression is x^2 +6x +7 ? could it be X^2 +6x -7 ?

OpenStudy (anonymous):

It's +7

OpenStudy (anonymous):

Can you help?

OpenStudy (***[isuru]***):

so we got no choice but to make it an perfect square ... Do u know how to do that ?

OpenStudy (anonymous):

No

OpenStudy (anonymous):

Use from Quadratic equation and find each X s is < 0 :)

OpenStudy (anonymous):

Can't I solve this by graphing?

OpenStudy (anonymous):

Yep ! Mabey !

OpenStudy (***[isuru]***):

of course ..... Y not ?

OpenStudy (anonymous):

But I see two better way !

OpenStudy (anonymous):

I know how to solve it graphically, but i'm not getting any of my answer choices

OpenStudy (anonymous):

One : kill 6x and answer :) 2 : Use from Quadratic equation My idea is 2 :)!

OpenStudy (***[isuru]***):

tell me the way u graph it ? wt was ur function ?

OpenStudy (anonymous):

I just graphed x^2+6x+7 and looked where it crossed the x-intercept, and got -4.4<x<-1.58 which is also equal to \[\left[ -3-\sqrt{2}, -3+\sqrt{2} \right]\]

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