Solve the inequality and express your answer in interval notation.
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OpenStudy (anonymous):
\[x ^{2}+6x+7<0\]0
OpenStudy (***[isuru]***):
Hi,
r u sure that the expression is x^2 +6x +7 ? could it be X^2 +6x -7 ?
OpenStudy (anonymous):
It's +7
OpenStudy (anonymous):
Can you help?
OpenStudy (***[isuru]***):
so we got no choice but to make it an perfect square ... Do u know how to do that ?
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OpenStudy (anonymous):
No
OpenStudy (anonymous):
Use from Quadratic equation and find each X s is < 0 :)
OpenStudy (anonymous):
Can't I solve this by graphing?
OpenStudy (anonymous):
Yep !
Mabey !
OpenStudy (***[isuru]***):
of course ..... Y not ?
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OpenStudy (anonymous):
But I see two better way !
OpenStudy (anonymous):
I know how to solve it graphically, but i'm not getting any of my answer choices
OpenStudy (anonymous):
One :
kill 6x and answer :)
2 :
Use from Quadratic equation
My idea is 2 :)!
OpenStudy (***[isuru]***):
tell me the way u graph it ? wt was ur function ?
OpenStudy (anonymous):
I just graphed x^2+6x+7 and looked where it crossed the x-intercept, and got -4.4<x<-1.58 which is also equal to \[\left[ -3-\sqrt{2}, -3+\sqrt{2} \right]\]