Find the error. −5(x + 4) + 21 ≥ −3 + 4(x − 8) −5x − 20 + 21 ≥ −3 + 4x − 32 −5x + 1 ≥ 4x − 35 −9x ≥ −36 x ≥ 1
When dividing by −9, he did not change the ≥ to ≤. He subtracted 4x from both sides when he should have added 5x. He subtracted 1 from both sides when he should have added 36. He did not make a mistake
\(\bf -5(x + 4) + 21 \ge -3 + 4(x - 8)\\\\ \quad \\ -5x - 20 + 21 \ge -3 + 4x - 32\\\\ \quad \\ -5x + 1 \ge 4x - 35\\\\ \quad \\ \color{red}{-9x \ge -36\\\\ \quad \\ x \ge 1}\)
notice anything there?
Same thing as the equation above. right?
well... what do you mean?
It's the same as what I put.
ohh yes
So I didn't notice anything different..
well, true... I didn't say check for typos, I meant, do you notice anything wrong in the simplification?
the last step will be x<or equal to 4
bcoz when u cancel negative sign on both the sides...the sign will also chnge...it will become less than..and it will be 4 as 36/9 is 4 not 1
so, the error is not switching the signs around ?
well, check again, what do you think is the error?
or....try to simplify it yourself, see what you get
jst check the last two steps...wat is 36 divided by 9?
1 or 4?wt d o u think?
4
yes right..and as i said...if negative sign is present on both the sides..it gets cancelled and the sign chnages.dis is a rule...if u cancel negative on both side sign of equality chnges.u have to remeber dis.
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