Question

Suppose that 5 cards are taken without replacement from a deck of 52 cards. how many ways are there to do this so that there are 2 red cards and 3 black cards?

Answer 1

In a deck of cards, how many cards are red and how many are black?

Answer 2

26

Answer 3

Right.
For the first pick, what is the probabiltiy of picking a red card?

Answer 4

26/52

Answer 5

Or 1/2

Answer 6

Good.
P(first card red) = 26/52

Now there are 51 cards left in the deck, 25 red, 26 black.
What is the probabillity of the second pick being red?

Answer 7

25/51

Answer 8

Good.
P(second card red) = 25/51

Now there are 50 cards left in the deck, 24 red, 26 black.
What is the probabillity of the third pick being black?

Answer 9

26/50, 25/49, 24/48

Answer 10

But I want to kno how many ways to make this hand, no the probability

Answer 11

Sorry. I misread the problem.

Answer 12

It's ok lol

Answer 13

Since you have 26 red cards to choose from, the first card is one out of 26 cards.
The second red card is one out of 25 cards.

Then for the black cards, the first one is one out of 26, the next one is one out of 25 left, and the third black card is one of 24 black cards left.

The total number is:
26 * 25 * 26 * 25 * 24

Answer 14

Oh that's it? Guess I read way to into it... Thank you

Answer 15

wlcm