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Solve the equation by factoring. 4x^2 + 12x = 0
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SO I factored it to 4(x+3x) = 0 And so now should I divide the left by 4 so that it's \[\frac{ x+3x }{ 4 }=0\] or does tht make no sense to do? (Because it doesn't make sense to me)
oops this was a dumb question. sorry
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4x^2+12x=0 4x(x+12)=0 x=0 or -12
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x = 0, -3.
No.
x=0 or -12
U factored it incorrectly. Look at mine
Factor out 4x not just 4
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Well the program for my homework says im right
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